Given that \(\frac{5^{n +3}}{25^{2n -3}}\) = 5º, find n
\(\frac{5^{n +3}}{25^{2n -3}} = 5^0\) \(\frac{5^{n + 3}}{5^{2(2n - 3)}} = 5^0\) n + 3 - 4n + 6 = 0 -3n + 9 = 0 -3n = -9 n = \(\frac{-9}{-3}\) n = 3
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