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Given that \(\frac{5^{n +3}}{25^{2n -3}}\) = 5º, find n

Mathematics
WAEC 2010

Given that \(\frac{5^{n +3}}{25^{2n -3}}\) = 5º, find n

  • A. n = 1
  • B. n = 2
  • C. n = 3
  • D. n = 5
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Correct Answer: Option C
Explanation

\(\frac{5^{n +3}}{25^{2n -3}} = 5^0\)

\(\frac{5^{n + 3}}{5^{2(2n - 3)}} = 5^0\)

n + 3 - 4n + 6 = 0

-3n + 9 = 0

-3n = -9

n = \(\frac{-9}{-3}\)

n = 3


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