Given that \(\frac{5^{n +3}}{25^{2n -3}}\) = 5º, find n
n = 1
n = 2
n = 3
n = 5
Explanation
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Discussions (19)
i found d mistake.5 power 0 is 1,nt 0.wit dat sorted out,d answer is 2.67
No the ans is 1/3, if you check the workings well, you would see that there are irregularities in the question.
HEY GUYZ,I must tell u dat dis question is based on INDICES but I am still confused.Someone should correct me in anystep i got wrong.
5^n+3/25^2n-3 =5^0.
firstly,in dis question,5 appeared bothsides, so i made 25 to be like d others by doing this,[5]^2.
I had 5^n+3/5^2[2n-3] =5^0.I Dealt with d bracket so dat i have,5^4n-6.
In indices,wherever u see division sign[/],u subtract.Since dey all have 5,neglect d 5 for now.
So, we have n+3-4n-6 =0.Dis 0 appeared here bcos dey all have 5 in common and so,dey will cancel each other and then they are gone so dat we have 0 after dat"="sign.
Then we collect like terms, like dis,
n-4n+3-6=0, then its =-3n-3=0,then -3n=0+3,then=-3n=3,then,n=3/-3,n=-1.
