In the diagram, IG is parallel to JE, JEF = 120o and FHG = 130o,... - Myschool

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In the diagram, IG is parallel to JE, JEF = 120o and FHG = 130o,...

In the diagram, IG is parallel to JE, JEF = 120^o and FHG = 130^o, fins the angle marked t

A. 40^o
B. 70^o
C. 80^o
D. 100^o

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Correct Answer: Option B

Explanation

Now, t + 60^o + 50^o = 180^o

t = 180^o - 110^o

t = 70^o

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