Mathematics
WAEC 2009
PQRS is a trapezium. QR//PS, /PQ/ = 5cm, /OR/ = 6cm, /PS/ = 10cm and angle QPS = 42
o. Calculate, correct to the nearest cm
2, the area of the trapezium (h = 3.35cm
2 )
-
A.
27cm2
-
B.
30cm2
-
C.
36cm2
-
D.
37cm2
Correct Answer: Option A
Explanation
Area = \(\frac{1}{2}(a + b)\)h
where a = QR = 6cm
b = PA = 10cm
Area = \(\frac{1}{2}(6 + 10)\) x 3.35cm
2
= \(\frac{1}{2}(16)\) x 3.35cm
2
= 26.8cm
2
= 27cm
2 (approx.)
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