If log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log (\(\frac{28}{3}\))
log (\(\frac{28}{3}) = \log (\frac{7 \times 4}{3})\)
= log 7 + log 4 - log 3
log 7 + log 22 - log 3 = log 7 + 2 - log 3
= z + 2x - y
= 2x + z - y
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