If log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log (\(\frac{28}{3}\))

a

2x + y - z

b

2x + z - y

c

x + y - 2x

d

x + x - y

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Correct Option
b

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Discussions (9)

itz_Charis
9 months ago

where did the 4 come from

bnino3311
9 years ago

Yes youre right

sadajc
1 year ago

excuse me

EniolaSae
3 years ago

No answer

regony600
9 years ago

It should be 2x+z-y

Raphael019
1 year ago

Incorrectly typed

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