If \(2^n = 128\), find the value of \(2^{n - 1})(5^{n - 2})\)
2n = 128 2n = 27 n = 7 (2n - 1)(5n - 2) = (2n - 2.2)(5n - 2) put n = 7 (2n - 1)(5n - 2) = 2(2n - 2 x 5n - 2) = 2(2 x 5)n - 2 = 2(10n - 2) put n = 7 (2n-1)(5n-2) = 2(105)
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}