Correct Answer: Option A

Explanation

Given; x = 2; y = \(\frac{-1}{4}\)

= \(\frac{x^2y - 2xy}{5}\)

= \(\frac{2^2(\frac{-1}{4}) - 2(2)(\frac{-1}{4})}{5}\)

= \(\frac{4(\frac{-1}{4}) + 4(\frac{-1}{4})}{5}\)

= \(\frac{1 + 1}{5}\)

= \(\frac{0}{5}\)

= 0

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