Given that x = 2 and y = -\(\frac{1}{4}\), evaluate \(\frac{x^2y - 2xy}{5}\)

a

zero

b

\(\frac{1}{5}\)

c

1

d

2

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a

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steelzZz
9 years ago

The question is wrong because in the question it was x-square that was given, looking at the solution it was actually x-square y that is suppose to be there...

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