\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1...

WAEC 2006

\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline y & 0.5 & 1 & 2.5\end{array}\). The table below satisfies the relation y - k\(\sqrt{x}\), where k is a positive constant. Find the value of P,

A. 2
B. 4
C. 10
D. 25

Project Topics and Materials, Post-UTME past questions - Download now or upload yours to get paid

Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts

Correct Answer: Option D

Explanation

From y = \(\frac{1}{2} \sqrt{x}\)

when y = 2.5 or \(\frac{5}{2}\), x = P

\(\frac{5}{2} \times \frac{1}{2} \sqrt{P}\)

\(\sqrt{P} = \frac{10}{2} = 5\)

P = 5²

= 25

Previous Next

Go back to Maths classroom

Report an Error Ask A Question Download App