The probability of a student passing any exam is 2/3. If the student takes three exams, what is the probability that he will not pass any of them?
P(not passing exam) = \(1 - \frac{2}{3} = \frac{1}{3}\)
P(not passing any of the three exams) = \(\frac{1}{3} \times \frac{1}{3} \times \frac{1}{3}\)
= \(\frac{1}{27}\)
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