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Find the maximum value of y in the equation y = 1 - 2x -...

Mathematics
JAMB 2002

Find the maximum value of y in the equation y = 1 - 2x - 3x\(^2\)

  • A. 5/4
  • B. 5/3
  • C. 3/4
  • D. 4/3
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Correct Answer: Option D
Explanation

\(y = 1 - 2x - 3x^2\)

At maximum point, \(\frac{\mathrm d y}{\mathrm d x} = 0\)

\(\frac{\mathrm d y}{\mathrm d x} = -2 - 6x\)

\(-2 - 6x = 0 \implies -2 = 6x\)

\(x = -\frac{1}{3}\)

At x = \(-\frac{1}{3}\), y = \(1 - 2(-\frac{1}{3}) - 3(-\frac{1}{3})^{2}\)

= \(1 + \frac{2}{3} - \frac{1}{3}\)

= \(\frac{4}{3}\)


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