Evaluate \(\int \sin 3x \mathrm d x\)
\(\int \sin 3x \mathrm d x = - \frac{\cos 3x}{3} + c\)
= \(-\frac{1}{3} (\cos 3x) + c\)
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}