Find the derivative of \(y = \sin^{2} (5x)\) with respect to x.

a

10 sin 5x cos 5x

b

5 sin5x cos 5x

c

2 sin 5x cos 5x

d

15 sin 5x cos 5x

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a

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AbdulmalikBello
6 years ago

y=sin'2(5x)
using the chain rule
let u=sin5x
y=u'2
dy/du=2u
du/dx=5cos5x
dy/dx=dy/du.du/dx
dy/dx=2u.5cos5x
dy/dx=2(sin5x).5cos5x
dy/dx=10sin5x.cos5x

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