Correct Answer: Option B

Explanation

A = \(\int^{x = 4}_{x = 0}\) ydx = \(\int^{4}_{0}\)16 -  x\(^2\)dx = [16 - \(\frac{x^3}{3} + c]^{4}_{0}\)

= \(\frac{128}{3}\) square units

There is an explanation video available below.

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