If the diagram is the graph of y = x\(^2\), the shaded area is
A = \(\int^{x = 4}_{x = 0}\) ydx = \(\int^{4}_{0}\)16 - x\(^2\)dx = [16 - \(\frac{x^3}{3} + c]^{4}_{0}\) = \(\frac{128}{3}\) square units
There is an explanation video available below.
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