A chord of a circle radius \(\sqrt{3cm}\) subtends an angle of 60° on the circumference of he circle. Find the length of the chord
Length of chord = \(2r \times \sin(\frac{\theta}{2})\)
= \( 2 \times \sqrt{3} \times \sin(\frac{60}{2})\)
= \(2 \times \sqrt{3} \times \frac{1}{2}\)
= \(\sqrt{3}\) cm.
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