A chord of a circle radius \(\sqrt{3cm}\) subtends an angle of 60° on the circumference of he circle. Find the length of the chord
a
\(\frac{\sqrt{3}}{2}\)
b
\(\frac{3}{2}\)
c
3
d
\(\sqrt{3}\)cm
Explanation
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Discussions (3)
Adeola19b
5 years ago
the answer is 3(Option C.
x= 2*r*tan(theta)/(sqrt(1+(tan(theta))^2)
x= [2*√3*tan60]/[ sqrt(1+(tan60)^2)]
tan60=√3
x= [2*√3*√3]/[sqrt(1+(√3)^2]
x=[2*3]/[sqrt(1+3)]
x=[6]/[2]
x=3cm
Britain
6 years ago
The answer is √3 because the formula for the lenght of a chord is 2r × sin (ø/2).2√3sin30= √3.
