In the diagram, QTR is a straight line and < PQT = 30°. Find the sin of < PTR
\(\frac{10}{\sin 30^o} = \frac{15}{\sin x} = \frac{10}{0.5} = \frac{15}{\sin x}\) \(\frac{15}{20} = \sin x\) sin x = \(\frac{15}{20} = \frac{3}{4}\) N.B x = < PTR
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