TQ is tangent to circle XYTR, &lt; YXT = 32o, RTQ = 40o. find&nbsp;&lt; YTR

TQ is tangent to circle XYTR, < YXT = 32o, RTQ = 40o. find < YTR

Mathematics

JAMB 1998

TQ is tangent to circle XYTR, < YXT = 32o, RTQ = 40o. find < YTR

A. 108^o
B. 121^o
C. 140^o
D. 148^o

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Correct Answer: Option A

Explanation

< TXR = < QTR = 40o (alternate segment)

< TWR = < TXR = 40o(Angles in the same segments)
< YXR = 40o + 32o = 72o

< YXR + < YTR = 180o(Supplementary)

72o + < YTR = 180o

< YTR = 180o - 72o

= 108o

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TQ is tangent to circle XYTR, < YXT = 32o, RTQ = 40o. find < YTR

Correct Answer: Option A

Explanation

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