Correct Answer: Option B

Explanation

TH = tan 45o, TH = QH

\(\frac{TH}{5 + QH}\) = tan 30o

TH = (b + QH) tan 30o

QH = 56 (5 + QH) \(\frac{1}{\sqrt{3}}\)

QH(1 - \(\frac{1}{\sqrt{3}}\)) = \(\frac{5}{\sqrt{3}}\)

QH = \(\frac{5\sqrt{3}}{\sqrt{3}} - \frac{1}{\sqrt{3}}\)

= \(\frac{5}{\sqrt{3} - 1}\)

• if 5^(2x)=125 find x? Answer this

  3 Answers   ·   Mathematics   ·   4 days ago
• how does post utme looks like and what are the subjects required for a medical student? Answer this

  2 Answers   ·   2 days ago
• What are the male and female reproductive hormones in animals? Answer this

  4 Answers   ·   Agricultural Science   ·   2 days ago