Correct Answer: Option D

Explanation

In △ UQV 

|UV|\(^2\) = 6\(^2\) + 4\(^2\)  (Pythagora's theorem)

|UV| = \(\sqrt{52}\) = 7.21cm

Also, in △ WVR

|WV|\(^2\) = 2\(^2\) + 2\(^2\) = 4 + 4 = 8 (same reason as above)

|WV| = \(\sqrt{8}\) = 2.83

Therefore, the area of △ UVW = \(\frac{1}{2}\) x 2.83 x 7.21 = 10.21 ≈ 10cm\(^2\)

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