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In the figure, PS = QS = RS and QSR - 100o, find QPR

Mathematics
JAMB 1990
In the figure, PS = QS = RS and QSR - 100o, find QPR
  • A. 40o
  • B. 50o
  • C. 80o
  • D. 100o
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Correct Answer: Option B
Explanation
Since PS = QS = RS

S is the centre of circle passing through P, Q, R /PS/ = /RS/ = radius

QPR \(\pm\) \(\frac{100^o}{2}\) = 50o
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