If PST is a straight line and PQ = QS = SR in the diagram, find y.
∠PSQ = ∠SPQ = 24 ( base ∠s of iso △)
∠SQR = <PSQ + <SPQ [ 1 ext < = 2 int. <s]
QSR = 180 - 2(48) = 84º ( vertical < of an iso △)
Now at S: y + 24º + 84º = 180 ( sum of <s on a straight line)
y = 180 - 108º = 72º
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