In the figure, PS = RS = QS and QSR = 50°. Find QPR
In the figure PS = RS = QS, they will have equal base QR = RP In angle SQR, angle S = 50º In angle QRP, 65 + 65 = 130º Since RQP = angle RPQ = \(\frac{180 - 130}{2}\) = \(\frac{50}{2} = 25^o\) QPR = 25°
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