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In the figure, PS = RS = QS and QSR = 50°. Find QPR

Mathematics
JAMB 1988

In the figure, PS = RS = QS and QSR = 50°. Find QPR

  • A. 25O
  • B. 40O
  • C. 50O
  • D. 65O
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Correct Answer: Option A
Explanation

In the figure PS = RS = QS, they will have equal base QR = RP

In angle SQR, angle S = 50º

In angle QRP, 65 + 65 = 130º

Since RQP = angle RPQ = \(\frac{180 - 130}{2}\)

= \(\frac{50}{2} = 25^o\)

QPR = 25°


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