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In the figure, STQ = SRP, PT = TQ = 6cm and QS = 5cm....

Mathematics
JAMB 1988

In the figure, STQ = SRP, PT = TQ = 6cm and QS = 5cm. Find SR
  • A. \(\frac{47}{5}\)
  • B. 5
  • C. \(\frac{32}{5}\)
  • D. \(\frac{22}{5}\)
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Correct Answer: Option A
Explanation
From similar triangle, \(\frac{QS}{QP} = \frac{TQ}{QR} = \frac{5}{12} = \frac{6}{QR}\)

QT = \(\frac{6 \times 12}{5} = \frac{72}{5} = SR = QR - QS\)

= \(\frac{72}{5} - 5 = \frac{72 - 25}{5}\)

= \(\frac{47}{5}\)

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