In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QPR = \(\theta\)o and RQP = \(\phi\)o, which of the following relationships between \(\theta\)o and \(\phi\)o is correct

\(\theta\)^o + \(\phi\)^o = 90²

\(\phi\)^o = 90² - 2\(\theta\)^o

\(\theta\)^o = \(\phi\)^o

\(\phi\)^o = 2\(\theta\)^o

\(\theta\)^o + 2\(\phi\)^o

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FAECSB7610542

11 months ago

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FAECSB7610542

1 year ago

I guess there's a little error there, but I think it should be this way; in the diagram I posted below:
x = ϕ° + θ°, but instead in the solution they did 180° - ϕ° = θ° + ϕ°, which is wrong, if you should look at the diagram below, in ∆QPR,