PQRS isa cyclic quadrilateral which PQ = PS. PT is a tangent to the circle and PQ makes an angle of 50o with the tangent as shown in the figure. What is the size of QRS?
< PSQ = < QPT = 50º
In \(\triangle\) PQS, PS = PQ (given) base angles of an isosceles triangle.
< QRS = 180º - < SPQ (opp <s of a cyclic quad)
<QRS = 180º - 80º = 100º
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