In the figure, PS = SR and Rx is a tangent to the circle at R, < QRX is equal to 72o. Find angle SPR
XRQ = RSQ (Alternate segment) s = 72o (80o - 72o = 180o) a + b + c = 190o = 2b + c = 180o 2b + 108 = 180o 2b = 72o b = 36o
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