In the figure, PS = SR, and Rx is a tangent to the circle at R. < QRX is equal to 72º. Find angle SPR
<XRQ = <RSQ (Alternate segment)
<SRQ = 72º
<PSR = 180º - 72º = 108º
a + b + c = 180o = 2b + c = 180o
2b + 108 = 180o
2b = 72o
b = 36o
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