In the figure, If PT is parallel to RS, PQ = PT, and angle SQT = 90o, Find x

Emmysam9

6 years ago

i don't know how to solve pls help

Smartdaddy69

2 years ago

I have an issue here, a really big one i chose 70 cause it was the closest number to my calculations(which was 68), I was not happy at all and I've noticed consistently that every time I take the practice test (35min) the first mathematics question always has an issue, pls don't frustrate me yall. making me doubt my mathematical talent

Uchebuka

3 years ago

The answer to this question is not in the options, it is not 70. Use the theorem of "exterior angles". 56 + x will give an exterior angle that would be, lets say "m"--- equ.1. But m = 90 + an unknown angle "y". Therefore, m = 90 + y. Extending line PQ to the left to a point A, we see that angle SRQ is equivalent to angle TPA which is x. Now extending line TQ and SQ downwards we see that angle TQP is y, and since it's an isoceles triangle PTQ will also be y. Again, applying the exterior angle theorem, we see that angle TQP + PTQ, which is y+y will be equal to the exterior angle TPA which is x. Therefore, 2y = x---equ. 2. Inputing 2y for x in angle SRQ would be, 56 + 2y and inputing in equ. 1 would be, 56 +2y = m. Remember m = 90 + y, therefore, 56+2y = 90 + y, therefore, solving for y, y = 34. Put y = 34 in equ. 2, therefore, x = 34 x 2 = 68, which is the answer.

Uchebuka

3 years ago

N:B: The unknown angle y is revealed from the extention of TQ and SQ

Fave.x

1 year ago

abeg explain

succy34

1 year ago

I don't understand please

Obama08

1 year ago

I thought

12345ife

3 months ago

both the question and the answer is not the same

protobi

2 years ago

There was no diagram in the question

Timiz01

3 years ago

pls oo explain how you got 70 because i solve and got 55