Correct Answer: Option B

Explanation

\(\frac{x + 3}{sin 60^o}\) = \(\frac{x}{sin 306o}\)

3sin 30^o = x sin 60^o - x sin 30^o

= x(sin 60^o - sin 30^o)

but sin 30^o = \(\frac{1}{2}\)

sin 60^o = \(\frac{3}{2}\) = \(\frac{3(\sqrt{3} - 1)}{\sqrt{3} + 1}\)

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