Correct Answer: Option D

Explanation

If < CED = 30º, and < EDA = 40º then

<EOD = 180-(30-40) (angles in a triangle sum to 180) → 110º

<AOC = <EOD = 110º

At centre O: 360 - 110 = 250º

The angle subtended by an arc of a circle at its center is twice the angle it subtends anywhere on the circle's circumference.

250 * \(\frac{1}{2}\) → 125º

<ABC = 125º

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