The angle of elevation of the top of a vertical tower from a point A on the ground is 60o. From a point B, 2 units of distance further away from the foot of the tower, the angle of elevation of the tower is 45o. Find the distance of A from the foot of the tower
3 + \(\sqrt{3}\)
5 + \(\sqrt{3}\)
3 - \(\sqrt{3}\)
1
\(\sqrt{3}\) + 1
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pls can someone explain 1978jamb maths
the one that says "angle of elevation of the top of a vertical tower from a point A on the ground id 60°......."
you people can't get it until you understand the question itself
i failed it when i tried it
but after seeing the answer i understand it a lot more
if you would like ne to out you through let ne know
it's not hard you just need to understand the basics
