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A triangle has angles 30o, 15o and 135o. The side opposite to the angle 30o...

Mathematics
JAMB 1978

A triangle has angles 30o, 15o and 135o. The side opposite to the angle 30o is length 6cm. The side opposite to the angle 135o is equal to

  • A. 12cm
  • B. 6cm
  • C. 6\(\sqrt{2}\)cm
  • D. 12\(\sqrt{2}\)cm
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Correct Answer: Option C
Explanation

\(\frac{6}{\sin 30}\) = \(\frac{x}{\sin 135}\)

\(\frac{6}{\sin 30}\) = \(\frac{x}{\sin 45}\)

x = \(\frac{6 \times \sin 45}{\sin 30}\)

= \(6 \sqrt{2}\)cm


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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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