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If \(3x - (\frac{1}{4})^{-\frac{1}{2}} > \frac{1}{4} - x \), then the interval of values of x is

Mathematics
JAMB 1978

If \(3x - (\frac{1}{4})^{-\frac{1}{2}} > \frac{1}{4} - x \), then the interval of values of x is

  • A. x > \(\frac{1}{3}\)
  • B. x < \(\frac{1}{3}\)
  • C. x < \(\frac{1}{4}\)
  • D. x < \(\frac{9}{16}\)
  • E. x > \(\frac{9}{16}\)
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Correct Answer: Option E
Explanation

\(3x - (\frac{1}{4})^{-\frac{1}{2}} > \frac{1}{4} - x\)

= \(3x - 4^{\frac{1}{2}} > \frac{1}{4} - x\)

= \(3x - 2 > \frac{1}{4} - x\)

= \(3x + x > \frac{1}{4} + 2 \implies 4x > \frac{9}{4}\)

\(x > \frac{9}{16}\)


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