Find the square root of 170 - 20\(\sqrt{30}\)

a

2 \(\sqrt{10}\) - 5\(\sqrt{3}\)

b

2 \(\sqrt{5}\) - 5\(\sqrt{6}\)

c

5 \(\sqrt{10}\) - 2\(\sqrt{3}\)

d

3 \(\sqrt{5}\) - 8\(\sqrt{6}\)

Download Offline App Ask a Question

Explanation

Correct Option
b

Video Explanation

No video available

Post your Contribution

Share:

Discussions (14)

Stacatto
7 years ago

et's say

√(170 - 20√30) = √a - √b

square both sides.

170 - 20√30 = (√a - √b)²

170 - 20√30 = a - 2√ab + b

170 - 20√30 = a + b - 2√ab

comparing coefficient

a + b = 170

a = 170 - b ----- (1)

-2√ab = -20√30

√ab = 10√30

square both sides.

ab = 100(30)

ab = 3000------(2)

sub (1) into (2)

b(170 - b) = 3000

170b - b² = 3000

b² - 170b + 3000 = 0

b² - 150b - 20b + 3000 = 0

b(b - 150) - 20(b - 150) = 0

b = 20 or 150

sub b in (1)

a = 170 - b

a = 150 or 20

Re : √(170 - 20√30) = √a - √b

= √150 - √20
=√25x6 - √5x4
=5√6 - 2√5

Jesusßoi
10 years ago

I don't understand this yet, I would be so glad if you could explain better.

Faithi06
2 years ago

I'm confused 🤔

Shawty_tj
1 year ago

NOT CLEAR

Anonymous2591606
11 months ago
Image

Note use this formula specifically for this equation, it's more faster, if you can cram it better for you but use it specifically for this equation;because it's a perfect square

Itunuokunade
3 months ago

or you can use plug and play

For option B
it 2 sqr root 5 and 5 sqr root 6
is 2×2×5,5×5×6. which is 150 plus

Itunuokunade
3 months ago

or you can use plug and play

For option B
it 2 sqr root 5 and 5 sqr root 6
is 2×2×5,5×5×6. which is 150 plus 20 which is 170

ava_llamaa
2 months ago

so this is what somebody should be solving in the exam hall 😭 egbami keh

Quick Questions

Ask a Question

abdullahibabajide63

22nd June, 2026


1 comments
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments