Correct Answer: Option A

Explanation

Sum of n terms of Geometric progression is \(S_{n} = \frac{a(1 - r^n)}{1 - r}\)

In the given series, a (the first term) = 1 and r (the common ratio) = x.

\(S_{n} = \frac{1(1 - x^{n})}{1 - x}\)

a = 1, and as n tends to infinity

\(S_{n} = \frac{1}{1 - x}\)

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