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Multiply (x + 3y + 5) by (2x2 + 5y + 2)

Mathematics
JAMB 1978

Multiply (x + 3y + 5) by (2x2 + 5y + 2)

  • A. 2x2 + 3yx2 + 10xy + 15y2 + 13y + 10x2 + 2x + 10
  • B. 2x3 + 6yx2 + 5xy + 15y2 + 31y + 5x2 + 2x + 10
  • C. 2x3 + 6xy2 + 5xy + 15y2 + 12y + 10x2 + 2x = 10
  • D. 2x2 + 6xy2 + 5xy + 15y2 + 13y + 10x2 + 2x + 10
  • E. 2x3 + 2yx2 + 10xy + 10y2 + 31y + 5x2 + 10
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Correct Answer: Option B
Explanation

\((x + 3y + 5)(2x^{2} + 5y + 2)\)

= \(2x^{3} + 5xy + 2x + 6yx^{2} + 15y^{2} + 6y + 10x^{2} + 25y + 10\)

= \(2x^{3} + 5xy + 2x + 6yx^{2} + 15y^{2} + 31y + 10x^{2} + 10\)

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WAEC offline past questions - with all answers and explanations in one app - Download for free
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995