If y = x\(^2\) - 2x - 3, find the least value of y and the corresponding value of x
x = 3, y = 3
x = 1, y = -3
x = 4, y = 1
x = 1, y = -4
x = 2, y = -3
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If Y= X^2 - 2x - 3. Find the least value of Y and the corresponding value of X...
In this let solve for Y first: (^) this means raise to power
Y= X^2 - 2x - 3
Let find Y taken X as 1
X=1
Y = (1)^2 - 2(1) -3
Y= 1 - 2 - 3
Y= -4
Now let use Y to find X
Y= X^2 - 2x - 3. (Y = -4)
-4 = X^2 - 2x - 3
Collect like terms
X^2 - 2X - 3 + 4 =0
X^2 - 2x +1 = 0
Now let find what's common using 2X
That's what two number you will add to get 2x and when you multiply it you get 1.
Which is 1+1 to give us 2, 1 * 1 to give us 1
But let the 1 be X
X^2 - 2x +1 = 0
(X^2 - X) - (X + 1)
X(X - 1) - 1(X - 1)
X - 1 =0.
X= 1
Therefore y =-4 , X =1
Answer is D...
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