The size of a quantity first doubles and then increases by a further 16%. After a short time its size decreases by 16%. What is the net increases in size of the quantity?

a

\(\frac{59300}{625}\)

b

\(\frac{50900}{625}\)

c

200%

d

+100%

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Explanation

Correct Option
c

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Discussions (9)

EAEmerson
1 year ago

the calculation is wrong and unclear:
Let's break it down step by step:

1. Initial Size = 100% (Assume 1 unit for simplicity).


2. First, the quantity doubles:

New size = 2 × 100% = 200% (or 2 units).



3. Next, it increases by 16%:

Increase = 16% of 200% = 0.16 × 200 = 32%.

New size = 200% + 32% = 232% (or 2.32 units).



4. Then, it decreases by 16%:

Decrease = 16% of 232% = 0.16 × 232 = 37.12%.

New size = 232% - 37.12% = 194.88% (or 1.9488 units).


5. Net Increase:

Initial size = 100%.

Final size = 194.88%.

Net increase = 194.88% - 100% = 94.88%.

Final Answer:

The net increase in size of the quantity is 94.88%.

UDclassic
2 years ago

I don't understand

Ele0357
1 year ago

I too don't understand

Adewinizu
1 year ago

same here

Havilah10
2 months ago

Myschool Pls can you update the answer thanks

chadlevy
2 months ago

59300 ÷ 625 is the correct answer (94.88)

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