An arc of circle of radius 2cm subtends an angle of 60º at the centre. Find the area of the sector
Area of a sector \(\frac{\theta}{360}\) x \(\pi\)r\(^2\) = \(\frac{60^o}{360^o}\) x \(\pi\)2\(^2\) = \(\frac{2 \pi}{3}\)cm2
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