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A.
\(\frac{1}{x}\)
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B.
\(\frac{1 - x}{x}\)
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C.
\(\frac{1 + x}{x}\)
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D.
\(\frac{1}{x - 1}\)
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E.
\(\frac{-x - 1}{1}\)
Correct Answer: Option C
Explanation
\(\frac{1 - x^2}{x - x^2}\), where x = \(\neq\) 0
\(\frac{1^2 - x^2}{x - x^2}\)
= \(\frac{(1 + x)(1 - x)}{x(1 - x)}\)
= \(\frac{1 + x}{x}\)
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