Simplify \(\frac{1 - x^2}{x - x^2}\), where x \(\neq\) 0
a
\(\frac{1}{x}\)
b
\(\frac{1 - x}{x}\)
c
\(\frac{1 + x}{x}\)
d
\(\frac{1}{x - 1}\)
e
\(\frac{-x - 1}{1}\)
Explanation
Correct Option
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fejisconcept
10 months ago
it's correct because 1² is expand ed as 1, then difference of two square will solve the rest
