On each market day Mrs. Bassey walks to the market from her home at a steady speed. This journey normally takes her 2 hours to complete. She finds, however, that by increasing her usual speed by 1 km/hr she can save 20 minutes. Find her usual speed in km/hr

a

1\(\frac{2}{3}\)

b

2

c

5

d

6

e

10

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Explanation

Correct Option
c

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Discussions (9)

Hakimziyech
3 years ago

t1=2hrs ; t2=2-0.33hrs(20mins)=1.67hrs ;
v2= v1+1
Distance =vt
since distance does not change we can say
v1t1=v2t2
2v1=(v1+1)1.67.....
v1=1.67/0.33
v1=5km/hr(approx.)
C is the correct answer.

Macon5000
2 years ago

t = 2-1/3 = 5/3
2v= (v+1)×5/3
2v= (5v+5)/3
cross multiply
6v = 5v +5
6v-5v = 5
v = 5✓

Please, admin and fellow students, I need a more detailed explanation

Seun488
1 year ago

I finished answering the jamb cbt questions and it restarted all over with my time remaining 18 min

Akinwale01
3 years ago

Have you been able to solve this question ?

askillven
6 years ago

y is 20 divided by 2, = 5 pls abeg my school ho wfar u nd answers

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