Correct Answer: Option B

Explanation

0 < \(\frac{x + 3}{x - 1}\) < 2

Put x = 0, -3 and 9

0 < \(\frac{9 + 3}{9 - 1}\) \(\leq\) 2

i.e. 0 < 1.5 \(\leq\) 2 (true)

but 0 < \(\frac{0 + 3}{0 - 1}\) \(\leq\) 2

i.e. 0 < -3 \(\leq\) 2 (not true)

-3 \(\leq\) 2

-3 is not greater than 0

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