Make c the subject of the equation a(b + c) + \(\frac{5}{d}\) - 2 = 0
a(b + c) + \(\frac{5}{d}\) - 2 = 0 ab + ac + \(\frac{5}{d}\) - 2 = 0 abd + \(\frac{acd}{d}\) + 5 - 2 = ab + ac + 5 - 2d acd = 2d - 5 - abd c = \(\frac{2d - 5 - abd}{ad}\)
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