Make c the subject of the equation a(b + c) + \(\frac{5}{d}\) - 2 = 0
a
c = \(\frac{2d - 5 - b}{ad}\)
b
c = \(\frac{2d - 5 - abd}{ad}\)
c
c = \(\frac{2d - 5 - ab}{ad}\)
d
c = \(\frac{5 - 2d - b}{ad}\)
Explanation
Correct Option
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Discussions (7)
marygoldi
4 months ago
a(b+c)+5/d-2=0
opening the bracket and collecting like terms:
ab+ac=2-5/d
slove for (2-5/d) first:
2/1-5/d
find the lcm of 1 and d
2-5/d
put 2-5 all over d in the equation back and cross multiply"
2d-5=abd+acd
make c suject of foluma by collecting like terms and dividing by ad
c=2d-5-abd/ad
Jkkkkkyyy
1 year ago
This questions said to make x the subject of the formula,I think the options are incorrect
