Correct Answer: Option E

Explanation

Cos Q = \(\frac{r^2 + p^2 - q^2}{2rp}\)

= \(\frac{10^2 + 8^2 - 6^2}{2(10)(8)}\)

= \(\frac{164 - 36}{160}\)

= \(\frac{128}{160}\)

= 0.8

Q = Cos^-1 o.8

= 37^o x rep. from rt< RSQ, Let RS = x

\(\frac{x}{sin 37^o}\) = \(\frac{8}{sin 90^o}\)

but sin 90^o = 1

x = 8 sin 37^o

x = 4.8cm

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